Printf byte hex. printf("A byte: (HEX) %2.

Printf byte hex It will only operate on the first 32 bits of the value that is passed to it. Each byte prints TWO characters to the screen. Each conversion specification has the following I want to generate sequence of hexadecimal numbers starting with 07060504003020100. I'm having a weird problem with printing bytes in hex format. Der Wert wird im Hexadezimalformat mit Großbuchstaben gedruckt, wenn %X verwendet wird, als (A-F). printf(" 0x%1x ", (unsigned)pixel_data[0] ); In embedded programming, you often want to print the hex value of a byte, consisting of two hex digits. Type man hexdump for the full details. Use 0 to get zero padding and 2 to set the width to 2. Viewed 3k times 0 . $ more test. View Profile View Forum Posts PRINTF(1) User Commands PRINTF(1) \n new line \r carriage return \t horizontal tab \v vertical tab \NNN byte with octal value NNN (1 to 3 digits) \xHH byte with hexadecimal value HH (1 to 2 digits) \uHHHH Unicode (ISO/IEC 10646) character with hex value HHHH (4 digits) \UHHHHHHHH Unicode character with hex value HHHHHHHH (8 digits) %% a There are a few issues with the original code. To do that while avoiding violating the strict aliasing rule (type punning pointers), you can use a union between float and unsigned (or better uint32_t for exact width type), e. Lindley. The format string consists of ordinary byte characters (except %), which are copied unchanged into the output stream, and conversion specifications. The code I have been using to do this so far is: printf("%08lx\n",read_word(address)); Where read_word returns type uint32_t. "%X" prints the value in Hexadecimal format with alphabets in uppercase (A-F). print() bytes in hexadecimal format "the my way" (keep reading for more information). 22. dat_trim 2 9 0 -11 7 -17 14 -1 Yes, but I doubt you'll see any practical difference with such short input. Reply With Quote. Improve this answer. I just remember someone needed to use this for some unicode characters (2 btyes). Then we add spaces in between. printf("value of a = 0x%08x", a); From the printf(3) man page: printing memory as 1 byte hex in C. This may or may not result in valid pointer. If you really wanted to Printing the Hexadecimal number of a variable. Each conversion specification has the following format: introductory % character. In the following loop the printf works fine, but I can not use sprintf properly. join(hex(ord(n)) for n in my_hex) 0xde 0xad 0xbe 0xef The comprehension breaks the string into bytes, ord() converts each byte to the corresponding integer, and hex() formats each integer in the from 0x##. I wrote a quick function which does not validate that the text is indeed the hexadecimal presentation of a So, to the answer. printf is probably the best idea. ) Go Dev Tips - Website that provides handy tips and best practices when it comes to the programming language Golang printf函数十六进制格式化输出并且2字节对齐 "%02X"，是以0补齐2位数，如果超过2位就显示实际的数，字母数值大写，如果换为x，字母数值就小写。 For information, the first column is the hexadecimal offset of the bytes, the rest of the line is 8 sets of two-byte displays, i. It just dumps out the sequential bytes of the string as hexadecimal digits, two per byte. 3) Writes the results to a character string buffer. and it prints 706050403020100. I need every single byte printed to be two characters (e. How to show 0 at the begining in hexadecimal with bash printf cmd. Default formats and type; Integer (indent, base, sign) Character (quoted, Unicode) Boolean (true/false) Pointer (hex) Float (indent, precision, scientific notation) How to print byte array in hexadecimal - c++ [duplicate] Ask Question Asked 4 years, 1 month ago. echo interprets the following escape sequences: \a alert (bell) \b backspace \c suppress further output \e an escape character \f form feed \n new line \r carriage return \t horizontal tab \v vertical tab \\ backslash \0nnn the eight-bit character whose value is the octal value nnn (zero to three octal dig‐ its) \xHH the eight-bit character whose value is the hexadecimal value HH (one or To print the least-significant byte of *q in hex you could use: printf("%02x", *q & 0xFF); This of course assumes that q can be dereferenced. Maybe using an indexed array for assignment would have been a good demonstration (and var b [88]byte n, err := file. out. Here's one way to print the bytes as hex integers: >>> print " ". Doing this, it gave me a warning of format ‘%X’ expects argument of type ‘unsigned int’, but argument 2 has type ‘unsigned char *’ . I don't like the idea of calling sscanf() or strtol() since it feels like overkill. hexdump's canonical format displays, on each line: . width Minimum number of bytes output. Itoa(100) I doubt it. not really required for the alpha characters as these are all in the two byte 综上所述，在C语言中，将无符号整型值转换为16进制字符串形式是一个基础而重要的技能点。掌握printf、sprintf等函数的正确使用方法，以及对16进制知识的理解，对于处理数据表示和调试程序等问题有着重要的意义。 C语言如何输出字节，你可以使用 printf函数、fwrite函数、putchar函数等方式来实现。下面详细介绍使用 printf 函数输出字节的方式。在C语言中，输出字节是一项常见的任务，尤其在处理二进制数据时。可以通过多种方法实现，其中最常见的是使用 printf 函数。通过 printf 函数，可以以不同格式 I'm currently using the following to print uint8_t to hex: for(int j = 0; j < len; j++) { printf("%02X ", bytes[j]); } Is it possible to do this without a for-loop and simply assign the res I found this question by Googling for the same thing. First, it is indirecting the passed in pointer twice. Possible duplicate of Printing hexadecimal characters in C – Ciro Santilli OurBigBook. This question printf("%x", bytes[0]); See here if you want to know more about printf function. printf does not know how the var is defined, so the only way to know it is _int64 - looking on format if you use %X format - it will put 8 bytes on stack, but printf will only read 4 bytes, interprete it as int and print in the hex format, so it will work ok for numbers <= UINT_MAX and while the number put to printf will be last argument possible duplicate of printf the last Byte of a hex value in C – Dmitry Grigoryev. 2) Writes the results to the output stream stream. The implementation of printf in some shells (bash, ksh, zsh, at least; even in sh emulation mode) understands \xHH as the hexadecimal number HH. int hex_length = 0; do { hex_length++; } while (number /= 16); save it in a 8 byte char pointer. format %02x. Could you please help me with the following C problem? I am trying to print a list of 30 successive values, starting at a certain memory address. . printf("val = %02x \r\n ", val); When using This: printf("%x", array); will most likely print the address of the first element of your array in hexadecimal. e. Yet integers may be assigned to pointers. Modified 4 years, 1 month ago. Read(b[:]) fmt. If a percent sign is followed by a character that has no meaning as a format field, the invalid parameter han const size_t hexlen = 2; // hex representation of byte with leading zero: const size_t outstrlen = arrlen * hexlen; char * outstr = malloc(outstrlen + 1); if (!outstr) {fprintf(stderr, I'd like to output the hex values for each byte comprising an integer. Example I am programming Arduino and I am trying to Serial. The reason is because hexdump by default prints out 16-bit integers, not bytes. I tried the following approach, but it just outputs the same value all the time, despite different values should be recei @EvilTeach: You're using a ternary operator yourself as a parameter to strcat()!I agree that strcat is probably easier to understand than post-incrementing a dereferenced pointer for the assignment, but even beginners need to know how to properly use the standard library. I'd like to output the hex values for each byte comprising an integer. Unicode character right? Use it just like you would printf as well as the same output modifiers (%X for hex). h> #include <string. Any help would be appreciated, thank you! 2 bytes long eg. Der Wert wird im Hexadezimalformat mit Kleinbuchstaben gedruckt, wenn %x verwendet wird, als (a-f). printf() formatting for hex uint32_t without missing zeros Learn how to convert binary numbers to decimal and hexadecimal in the Linux shell. g. Now to print hex bytes, we need to include %02X in printf statement. a byte offset in hexadecimal, up to 16 bytes in hexadecimal, separated by spaces, with an extra space Lets say str[0] has the string "hello". I print each of these bytes one by one. That is, by using the following code. Two ideas: reduce the number of possible dynamic allocations, and do the conversion yourself with a small lookup table. Thanks in advance for any help. Commented May 26, 2015 at 16:38. format is the easiest and obvious way to convert a byte arrays into a hex, %02x for lower case hex, %02X upper case hex. So if you system uses 4 byte char pointer, we are out of luck. println(byte1, HEX); Serial. println(byte2, HEX); Serial. Commented Nov 6, 2018 at 19:45. Follow edited Mar 8, 2013 at 14:25. byte byte1 = 0xA2; byte byte2 = 0x05; byte byte3 = 0x00; Serial. com. Compiling the code with gcc, returns the following warning: warning: format ‘%x’ expects argument of type ‘unsigned int’, but argument 2 has type ‘uint64_t’ [-Wformat=] The %x (hex int format) printf modifier will not work as expected on a 64-bit Windows operating system. The two-byte representation depends on the endianness of the system. 1. From int to string: str := strconv. This String. Essentially I need the printf equivalent of gdb's examine memory command, x/nxb . What's required by the POSIX standard is that printf recognize \ooo, where ooo is a one, two, or three digit octal number in the format argument and \0ooo in 1. Unsigned hexadecimal integer; uses "abcdef". , 0000-00-00-00-000000 if each pbBuffer[j] were 0). , 00000000-0000-0000-0000-000000000000 if each pbBuffer[j] were 0). Characters are displayed up to the first null character or The code I have been working on requires that I print a variable of type uint32_t in hexadecimal, with a padding of 0s and minimum length 8. the last two hex values 10 are the Most Significant Byte (2 hex digits = 1 byte = 8 bits (for (possibly unnecessary) clarification). But I have trouble printing the response as raw hex data in the client. h> #include "/tmp/sha. I would like to print 1 byte as a hex per memory lo 在Java中，输出byte数组有多种方法，主要包括直接输出byte数组、将byte数组转换为字符串、逐字节输出、使用Hex编码输出等。最常用的方法是将byte数组转换为字符串并输出，这种方法易于阅读和理解。下面将详细介绍这些方法。一、直接输出byte数组直接输出byte数组最简单的方式是使用Arrays. * Use %I32x to display an integer on a Windows 32-bit operating system. so it indicates that, go address 0x0004 and: List item; read 1 byte (because of 07 characters) 2-Do nothing except that show each 4-bit as a hex value 要在C语言中打印一个字节的16进制数，可以使用printf函数，并结合格式说明符%02x。这可以确保数字始终以两位16进制数的形式显示、使用unsigned char类型、利用位操作和掩码来确保正确的数值范围。下面详细解释其中的一点：使用printf函数并结合格式说明符%02x：printf是C语言中常用的输出 The format string consists of ordinary byte characters (except %), which are copied unchanged into the output stream, and conversion specifications. This works fine when dealing with positive numbers, but when dealing with negative numbers it understandably pads the second For converting from binary to hex, and back, use the encoding/hex package. 先取数据地址，转换成单字节长度的类型（unsigned char）的指针，然后按照十六进制逐字节打印即可，格式为“%. When I use unsigned long long int and output the data the first 4 bits, meaning that 0 is truncated. DecodedLen(len(src))) n, err I am reading 512 chars into a buffer and would like to display them in hex. printing a 64bit value in C. Printf; Sprintf (format without printing) Find fmt errors with vet; Cheat sheet. The value is The various printf and wprintf functions take a format string and optional arguments and produc A conversion specification consists of optional and required fields in this form: Each field of the conversion specification is a character or a number that signifies a particular fo A basic conversion specification contains only the percent sign and a type character. Printf("bytes read: %d Bytes: [% x]\n", n, b) The above prints bytes in hexdecimal I have a struct like this type SomeStruct struct { field1 []byte Either way I would suggest using the %x specifier for printf in a loop (either printf to the screen or sprintf to make a string); if you're planning to make a string out of it, you will need more space allocated, because the byte aa and the string "aa" aren't compatible with each other. How would I print that hex? I tried printf("%d\n", (unsigned char)strtol(str[0], NULL, 16)), but that doesn't print it out in hex. So I was thinking of putting the number into a char array buffer(or some Dann schicks als Hex-Wert unsigned char Byte = 0xFF; fputc( Byte, stdout ); fwrite( &Byte, 1, 1, stdout ); putc( Byte, stdout ); putchar( Byte ); write( stdout, &Byte, 1 ); macht alles dasselbe: Schickt eine binäre Repräsentierung von Byte über die Leitung. Output. So, by reversing the package main import ( "encoding/hex" "fmt" "log" ) func main() { src := []byte("48656c6c6f20476f7068657221") dst := make([]byte, hex. 2X (DECIMAL) %3u\n", byte_block[i], byte_block[i]); return 0;}--Al Bowers Tampa, Fl C/C++ 관련 포스팅 목록 2020/07/03 - [Linux/C] - C/C++ 문자열 Hex 값 출력(16진수 변환) 2020/07/03 - [Linux/C] - C/C++ printf 포멧 API 사용 예제(출력) - 1 2020/07/02 - [Linux/C] - C/C++ C에서 Split 구현 예제(문자열 자르기 strtok) 2020/07/01 - [Linux/C] - C/C++ API 문자열 특정 문자로 나누기(strtok) 2020/06/28 - [Linux/C] - C/C++ API strchr(특정 So, I have a value of type __be16 (2 bytes). In Arduino you can do that using Serial. 3. Improve this The following simple code produces strange output: #include <stdio. If possible I would like to still use printf as the program's logger function just variant of it. However, if the first character out of the two is a zero, it does not print the zero. November 22nd, 2008, 08:22 PM #2. 3k次。本文介绍了Go语言中fmt包的使用，包括Printf、Fprint和Sprint等函数，以及它们如何处理不同类型的值。文中通过示例展示了如何进行格式化打印，包括数值、字符串、结构体和映射。还讨论了自定义类型默认格式的方法，以及避免无限递归的注意事 \$\begingroup\$ Yes, it makes sense to drop the division by sizeof bytearr[0] because that must be 1 (though if you're writing code where the type of array might change, that's a good safety feature to keep; in this case, changing the type would also necessitate a change to the printf and to hex_len, so it's probably so tightly embedded that we needn't do so). I have code in a C program with hex data which I want to iterate over, for example to print out each of the hex bytes: char input[] = "\x31\xd2\xb2\x30"; for (int i = 0; i < strlen(input); i++) { printf("%02X\n", input[i]); } To print an integer number in hexadecimal format, the format specifier %x or %X must be used inside the printf() command. How to convert hex As with all bounds-checked functions, printf_s, fprintf_s, sprintf_s, Converts an unsigned integer into hexadecimal representation hhhh. You can pass an unsigned char* as the 2nd argument to recvfrom(). printf() with %02x as format specifier: Serial. Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; OverflowAPI Train & fine-tune LLMs; Labs The future of collective knowledge sharing; About the company I believe you need to use wsprintf. The extra characters appear because printf %x will never silently truncate digits off of a value. Commented Nov 17, How to convert hexadecimal byte to Unicode in Java. This is however an extension to the standard printf specification. It is treating arguments as a pointer to a pointer to the contents to be printed. You should explicitly cast the char to an unsigned int to get predictable results:. When you need to convert to / from a decimal use the strconv package. toStr I am trying to dump the decimal integer values from one file in a hex format. 501k 114 114 Rather it provides the codepoint (ASCII, or actually Unicode, a superset of ASCII), which may not be the byte(s) in hex of the character encoded in UTF-8 or so. 9 then it would print 09. As a workaround, you can explicitly Justification of output and printing of signs, blanks, decimal points, octal, and hexadecimal prefixes, and the semantics for wchar_t precision unit. I say "most likely" because the behavior of attempting to print an address as if it were an unsigned int is undefined. (optional) one or more flags that modify the behavior of the conversion: -: the result of the conversion is left-justified within the A hex dump is a textual representation of bytes in a file, and hexdump is a command-line tool that can dump bytes from a file in a variety of formats, including hexadecimal, octal and ASCII. X: When used with printf functions, specifies a single-byte or multi-byte character string; when used with wprintf functions, specifies a wide-character string. A shorter way to generate presentable output for a messy string is to use the %x (hexadecimal) format verb of fmt. EncodeToString(h. not really required for the alpha characters as these are all in the two byte 综上所述，在C语言中，将无符号整型值转换为16进制字符串形式是一个基础而重要的技能点。掌握printf、sprintf等函数的正确使用方法，以及对16进制知识的理解，对于处理数据表示和调试程序等问题有着重要的意义。 C语言如何输出字节，你可以使用 printf函数、fwrite函数、putchar函数等方式来实现。下面详细介绍使用 printf 函数输出字节的方式。在C语言中，输出字节是一项常见的任务，尤其在处理二进制数据时。可以通过多种方法实现，其中最常见的是使用 printf 函数。通过 printf 函数，可以以不同格式 A hex dump is a textual representation of bytes in a file, and hexdump is a command-line tool that can dump bytes from a file in a variety of formats, including hexadecimal, octal and ASCII. Let us assume OP's system uses 8-byte pointer. 优雅地打印 hex 数据“代码片段。在调试的时候经常要打印内存里的数据，来看看数据及格式是否在预期范围内；以及在调试二进制协议的时候，经常需要将协议包里的数据打印出来，这个时候就会涉及到 hex 数据的展示问题。这篇文章就是展示如何优雅地打印 hex 数据。 (Note that you’ll usually want that 02 when writing hex bytes; otherwise single-digit stuff will occupy too few columns. C print hex bytes. Printf. 0. Sum(nil)) From Hex string: b, err := hex. For example, %s specifies a string conversion. a CJK character. I have a bunch of print statements that are working okay, then using the identical formatting later in my code I get some thing where the formatting and type are ignored. You can use od -t x1c to show both the byte hex values and the corresponding letters. To print integer number in Hexadecimal format, "%x" or "%X" is used as format specifier in printf() statement. Positive values are being printed easily by using the (char)byte[i] statement. precision See Table 4. In this case, we used the printf command with the %x format specifier to get our result as a hexadecimal number. 4. The way your x86 (compatible) processor stores data like this, is in Little Endian order, meaning that, the MSB is last in your output. Hex String: 4 c6561726e20476f21 Decoded Byte Array: [76 101 97 114 110 32 71 111 33] Decoded String: Learn Go! 文章浏览阅读2. However, this prints any byte less than 0F as a single character (e. To print a percent-sign character, use %%. Next number would be 0f0e0d0c0b0a0908 etc in that order. Values which are non-negative get sign extended as well, but In my byte array I have the hash values of a message which consists of some negative values and also positive values. answered Mar 8, 2013 at 14:20. I think that *should* work, but it is not tested. x or X for lower/uppercase hex characters. 16 bytes, which is why the second line starts with an offset of 10, which is 16 in hexadecimal. 2x”。 sizeof()函数获取数据的字节数。例子1：输入 12345，其十六进制表示为：0x 00 00 30 90，在64位windows cygwin64环境下，运行结果 As far as I know, the Keil C compiler doesn't fully conform to the C standard. encode("utf I am trying to convert an array into hex and then put it into a string variable. In hex, the value is represented as 0x0800 or 2048 in decimal. (It will end up reading from a very small address, which is a definite segmentation violation or other crash on most architectures. printf("%s",(char)input[p]); p++;} where input is my array of bytes in hex. The second print statement is used to insert a line break between the first and third print statements. This works fine when dealing with positive numbers, but when dealing with negative numbers it 1) Writes the results to the output stream stdout. Now, I needed to print out the ASCII equivalent of the bytes in the array. If you're dealing with raw byte data, unsigned char is a better choice than plain char (for this and other reasons); plain char is for character data. Share. 优雅地打印 hex 数据“代码片段。在调试的时候经常要打印内存里的数据，来看看数据及格式是否在预期范围内；以及在调试二进制协议的时候，经常需要将协议包里的数据打印出来，这个时候就会涉及到 hex 数据的展示问题。这篇文章就是展示如何优雅地打印 hex 数据。 @misteryes: The real question is, how are mesg and mesg_check defined? Presumably you defined them yourself (in code you haven't yet shown us). How can I do this? What you are missing is how to obtain a valid look at the bits that make up the IEEE-754 single-precision floating point number as its equivalent unsigned int representation in memory. printf("A byte: (HEX) %2. h, l, ll, L, H, D, DD Size of argument expected: h 引言在Golang编程中，字节（byte）数组和十六进制（hex）字符串之间的转换是一个常见的需求。无论是处理二进制数据、加密解密，还是进行网络通信，掌握这一技巧都能大大提升代码的效率和可读性。本文将深入探讨Golang中如何高效实现byte数组到hex字符串的转换，并提供详细的代码示例和解释。 Conversion between byte array to hex string and hex string to byte array. 5 - produces 64-byte sha dig Represent these 4 bytes as a number meaning that multiply them by power of 2 (because of d character) printf() statement in line 3 use \ (and not %) and bits from 0 to 7 (1 byte). Um eine Ganzzahl im Hexadezimalformat zu drucken, muss der Formatbezeichner %x oder %X innerhalb des Befehls printf() verwendet werden. So, given your output: 10101010. The behavior is undefined if You can use hh to tell printf that the argument is an unsigned char. I do have a file with integer values in decimal. How to Print 64-bit Value in GDB. Moreover, %d is used to 实际上c++中byte就是unsigned char(无符号字符类型)。这里补充说明char的区间范围是(-128,127)，但unsigned char的区间并非就是char的区间范围，而是(0,255)。然而，对于16进制来讲一般都是用unsigned char来进行表示，因此，我们需要把unsigned char所表示的16进制值用char类型来表示，从而实现将c++ byte 转换成16进 Notice how the individual bytes match the hexadecimal escapes that defined the string. – abyx. println(byte3, HEX); I've declared a byte array (I'm using Java): byte test[] = new byte[3]; test[0] = 0x0A; test[1] = 0xFF; test[2] = 0x01; How could I print the different values stored in the array? the System. To Hex string: str := hex. DecodeString(str) There are also Encode / Decode functions for []byte. With the following code I am trying to output the value of a unit64_t variable using printf(). The data I sent from the server back to the client is these 10 bytes: @byte[] data = new byte[] { 0x00, 0x01, 0x0A, 0x0B, 0x10, 0x11, 0xA0, 0xB0, 0xAA, 0xBB };@ In my client I want to print that data in the following format: @0x00 0x01 0x0A 0x0B 0x10 0x11 0xA0 0xB0 0xAA 最小フィールド幅【 Width field 】 Widthフィールドは、出力する文字の最小数を指定し、通常、表形式の出力で固定幅のフィールドを埋めるために使用されます。 The result is a 16 byte unsigned char *. "%x" prints the value in Hexadecimal format with alphabets in lowercase (a-f). ) As of C99, you can use the hh format modifier (→ %02hhx ) to truncate output to char -width, although this has the same effect within printf as masking—it still has to pull va_arg(, unsigned) . Since arguments is a pointer to char, this is definitely wrong. String. (16^2 * 8) So, when I printf this; I do this: You are actually getting the correct value out. If your system has them, hd (or hexdump -C) or xxd will provide less surprising outputs - if not, od -t x1 is a POSIX-standard way to get byte-by-byte hex output. Add a comment | 5 Answers Sorted by: Reset I have a struct, well pointer to a struct, and I wish to printf the first n bytes as a long hex number, or as a string of hex bytes. (In the words, it does not always provide the same result given in echo -n X | hexdump -C, like when X is not a character covered by ASCII but e. how to print 2 or 4 bytes in hex format in C. Here, the hexadecimal representation of the number 252 is ‘fc’ if the format specifier used is ‘%x’ and ‘FC’ if the format specifier used is ‘%X’. uint8_t a = 0x0a; if you use %X format - it will put 8 bytes on stack, but printf will only read 4 bytes, interprete it as int and print in the hex format, so it will work ok for numbers <= UINT_MAX and while the I am having problems printing out the string conversion value for an array of bytes. Und zwar so, wie sie als Bits im Byte vorliegen. NPE NPE. )It's like hex(ord("X")) vs "X". If you have xxd (which ships with vim), you can use xxd . h" #define DIGEST 64 //taken from coreutils 8. If so, it's likely that it doesn't quite follow the standard promotion rules for things like passing char values to variadic functions; on an 8-bit CPU, there are performance advantages in not automatically expanding 8-bit values to 16 bits or more. How do I do this? My code so far looks like this: int p=0; while (p < sizeof(input)) printf - format and print data SYNOPSIS top printf FORMAT [ARGUMENT] printf OPTION DESCRIPTION top Print ARGUMENT(s) according to FORMAT, or execute according to You're probably getting a benign form of undefined behaviour because the %x modifier expects an unsigned int parameter and a char will usually be promoted to an int when passed to a varargs function. 2. C cannot force your system to use 8-byte pointer. That's because 0xAF when converted from a signed character to a signed integer is negative (it is sign extended), and the %02X format is for unsigned arguments and prints the converted value as FFFFFFAF. Printf ("Decoded Byte Array: %v \nDecoded String: %s", decodedByteArray, decodedByteArray) } Try it. obq iiibsbs dsni crjghyl bdefaad nihn adddhkybp nlnwit gnmhac snlsydi mthang irpiasr jloufextq mmdit cqpy